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A job requiring 50,000 holes at 12 minutes per hole needs 10,000 spindle hours. At 75% utilisation, that is 7 single-spindle machines or 2 four-spindle machines on two shifts. A 20% error in this calculation means a $200,000–$800,000 mistake in capital allocation.
The Capacity Calculation Framework
Capacity planning for deep hole drilling follows a six-step process:
Annual Required Parts → Cycle Time per Part → Spindle Hours Required
→ Utilisation Adjustment → Shifts Calculation → Machine CountStep 1: Determine True Cycle Time
Cycle time for deep hole drilling includes much more than cutting time:
| Component | Example (25 mm Ø × 500 mm deep, 4140 steel) |
|---|---|
| Cutting time | 4.2 min (at 0.10 mm/rev, 1,200 RPM) |
| Peck retraction time | 1.8 min (8 retracts at 0.25 min each) |
| Tool change | 0.5 min |
| Part load/unload | 1.0 min |
| Coolant on/off delay | 0.3 min |
| Total cycle time | 7.8 min per hole |
Step 2: Calculate Spindle Hours Required
Spindle hours = (Annual parts × Cycle time per part) / 60
Example: 50,000 holes × 7.8 min / 60 = 6,500 spindle hours/yearStep 3: Apply Utilisation Rate
Realistic utilisation for deep hole drilling operations:
| Operation Type | Typical Utilisation | Notes |
|---|---|---|
| Single-shift, job shop | 50–65% | High changeover time |
| Single-shift, production | 65–80% | Dedicated setup |
| Two-shift, production | 70–82% | Shift change overlap |
| Three-shift, lights-out | 75–85% | Requires automation |
| Highly automated | 80–90% | Robotic loading |
Required machine hours = Spindle hours / Utilisation rate
Example: 6,500 / 0.75 = 8,667 machine hours/yearStep 4: Determine Shifts and Machines
Available hours per machine per year:
| Shift Pattern | Hours/Day | Days/Year | Available Hours |
|---|---|---|---|
| 1 shift | 8 | 240 | 1,920 |
| 2 shifts | 16 | 240 | 3,840 |
| 3 shifts | 24 | 240 | 5,760 |
| 3 shifts + weekends | 24 | 350 | 8,400 |
Machines required = Machine hours / Available hours per machine
Example (2 shifts): 8,667 / 3,840 = 2.3 machines → 3 single-spindle machinesMulti-Spindle Consideration
Multi-spindle machines change the calculation fundamentally:
| Configuration | Spindles | Equivalent Single-Spindle Machines | Capital Cost Comparison |
|---|---|---|---|
| Single-spindle | 1 | 1 | Base |
| Twin-spindle | 2 | 1.7–1.9 (some loss from shared tool changes) | 1.5–1.8× |
| Four-spindle | 4 | 3.2–3.6 | 2.5–3.5× |
| Six-spindle | 6 | 4.5–5.2 | 3.5–5.0× |
Multi-spindle becomes cost-effective above approximately 4,000–6,000 spindle hours per year on the same part.
Worked Examples
Example A: High-Volume Hydraulic Cylinder Bore
| Parameter | Value |
|---|---|
| Part | Hydraulic cylinder tube |
| Bore: 50 mm Ø × 1,200 mm deep | Material: ST52 |
| Cycle time | 14.5 min |
| Annual volume | 25,000 parts |
| Shift pattern | 2 shifts |
Spindle hours: 25,000 × 14.5 / 60 = 6,042 hours
Utilisation 78%: 6,042 / 0.78 = 7,746 hours
Available (2 shifts × 240 days): 3,840 hours
Machines: 7,746 / 3,840 = 2.0 → 2 single-spindle OR 1 twin-spindle BTAExample B: Low-Volume Aerospace Job Shop
| Parameter | Value |
|---|---|
| Part | Landing gear component |
| Bore: 12 mm Ø × 400 mm deep, Inconel 718 | |
| Cycle time | 22.3 min |
| Annual volume | 3,000 parts |
| Shift pattern | 1 shift |
Spindle hours: 3,000 × 22.3 / 60 = 1,115 hours
Utilisation 60%: 1,115 / 0.60 = 1,858 hours
Available (1 shift): 1,920 hours
Machines: 1,858 / 1,920 = 0.97 → 1 single-spindle gun drilling machineGrowth Capacity Planning
When planning capacity, allow for growth:
| Growth Scenario | Capacity Buffer |
|---|---|
| Stable demand | 10–15% |
| Moderate growth (5–10%/year) | 20–30% |
| High growth (15%+/year) | 30–50% |
| Unknown demand | 50% (lease extra capacity) |
FAQ
How do I estimate cycle time for a new part I have not drilled before?
Use gun drill manufacturers' recommended feeds and speeds, calculate cutting time, add 30–50% for peck retraction and idle time. Refine with actual test cuts.
What is a realistic utilisation rate for a first deep hole drilling operation?
65–70% for the first year. Do not plan for 80%+ until the process is stable and operators are experienced.
When should I choose multi-spindle over multiple single-spindle machines?
When the part volume exceeds approximately 4,000 spindle hours per year and the parts are similar enough that a single machine can run them without excessive changeover.
How does automation affect capacity planning?
Robotic loading increases utilisation by 10–15 percentage points by reducing load/unload time and enabling lights-out operation. A machine running 20 hours per day instead of 16 effectively adds 25% capacity without a second machine purchase.
Should I buy one large machine or two smaller ones?
Two smaller machines provide redundancy — if one is down for maintenance, the other keeps running. One large machine has lower capital cost per spindle but creates a single point of failure.
Capacity calculations depend on specific part geometry, material, and operating parameters. The examples in this article are illustrative. Perform detailed time studies on actual test cuts before committing to a machine configuration. This article reflects industry practice as of 2026.